Y = 1/(4 X^2) This problem has been solved!Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyCalculus Find dy/dx x^2y^2=2xy x2 y2 = 2xy x 2 y 2 = 2 x y Differentiate both sides of the equation d dx (x2 y2) = d dx (2xy) d d x ( x 2 y 2) = d d x ( 2 x y) Differentiate the left side of the equation Tap for more steps Differentiate Tap for more steps
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2xy(4-y^2)dx+(y-1)(x^2+2)dy=0-2x 3 2x 2 y 2xy 2 2y 3 = 2 • (x 3 x 2 y xy 2 y 3) Checking for a perfect cube 122 x 3 x 2 y xy 2 y 3 is not a perfect cube Final result 2 • (x 3 x 2 y xy 2 y 3) ————————————————————————— x 3 y 3 • (x y) 4Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the axis Sketch the region and a
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyPreAlgebra Examples Expand (x−y)(x2 −2xyy2) ( x y) ( x 2 2 x y y 2) by multiplying each term in the first expression by each term in the second expression Simplify each term Tap for more steps Multiply x x by x 2 x 2 by adding the exponentsAnswer to Determine the surface area of the portion of the paraboloid z = 4 x^2 y^2 that is above the xyplane By signing up, you'll get
Question Y' = 2xy^2;Graph y=1/2*(x4)^22 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and Since the value of is positive, the parabola opens up Opens Up Find the vertex Find , the distance from the vertex to the focusCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
There are two approaches to solve this (and are equivalent in the long run) But given that we have the following mathg(x)y' g'(x)y = f(x)/math where mathg(x) = 1x^2/math we can write mathg(x)y' g'(x)y = \frac{d}{dx}g(x)y /math soStack Exchange network consists of 177 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack ExchangeSimple and best practice solution for x^22xyy^2=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so
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Stack Exchange network consists of 177 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange Use Implicit Differentiation (and hope it all falls out the bottom) Differentiate both sides of the equation D (x^2y^2 xy) = D(2) using the product rule (a couple of times) and the chain rule (2x*y^2 x^2*2y*y') ((1)*y xy') = 0 giving y' (2yx^2 x) 2xy^2 y = 0 or y' = (2xy^2 y)/(2yx^2 x) We are asked for the points where the slope (y') equals 1 so (2xy^2The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction y^ {2}2xyx^ {2}=0 y 2 2 x y x 2 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2x for b, and x^ {2} for c in the quadratic formula,
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Instructor So let's write down a differential equation, the derivative of y with respect to x is equal to four y over x And what we'll see in this video is the solution to a differential equation isn't a value or a set of valuesX3yx2y2xy=0 Four solutions were found x = 2 x = 1 y = 0 x = 0 Step by step solution Step 1 Step 2 Pulling out like terms 21 Pull out like factors x3y x2y Consider x^ {2}2xy3y^ {2} as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest power x^ {2} and mSimplify (2xy)^3 (2xy)3 ( 2 x y) 3 Use the power rule (ab)n = anbn ( a b) n = a n b n to distribute the exponent Tap for more steps Apply the product rule to 2 x y 2 x y ( 2 x) 3 y 3 ( 2 x) 3 y 3 Apply the product rule to 2 x 2 x 2 3 x 3 y 3 2 3 x 3 y 3 23x3y3 2 3 x 3 y 3
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See the answer Show transcribed image text Expert Answer 100% (1 rating) Previous question Next question Transcribed Image Text from this Question y' = 2xy^2;Academiaedu is a platform for academics to share research papersEquations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations (7x^2y2/5xy^23)(5xy^24x^2y5)= so
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Por lo tanto, y = ~~116 Se perdió la solución y = 0 al dividir entre y'" Además, el problema de valor inicial, ecuación (13), tiene una cantidad infinitamente mayor de soluciones porque por cada elección del parámetro a 2 0 la funciónExactdifferentialequationcalculator 2xy^24=2(3x^2y)y', y(1)=8 en Related Symbolab blog posts Advanced Math Solutions – Ordinary Differential Equations Calculator, Linear ODE Ordinary differential equations can be a little tricky In a previous post, we talked about a brief overview of When I see terms x^n*diff(y(x),x,n) I always think to try a homogeneous solution of yh=x^r So yh'=r*x^(r1) and x*yh'2*yh=0 becomes x*r*x^(r1)2*x^r=x^r*(r2)=0 so r=2 and yh=k1/x^2 Since the rhs is a poly which is quadratic, we can try a par
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Explanation Using the chain rule by assuming y = y(x) we get 1 2 (5x y)− 1 2(5 y') = 2xy2 2x2yy' multiplying both sides by 2√5x y we obtain 5 y' = 4xy2√5x y 4x2yy'√5x y solving for y' y'(1 −4x2y√5x y) = 4x2y√5x y −5 so y' = 4xy2√5x y − 5 1 − 4x2y√5x ySteps Using the Quadratic Formula = { x }^ { 2 } { y }^ { 2 } 2xy1=0 = x 2 y 2 − 2 x y − 1 = 0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions,C U(x, y) = x2/3 y1/3 Since the indifference curves are bowed towards the origin, they do obey the assumption of diminishing MRS y x 8 8 1 1 512 512 Economics 3070 d U(x, y) =min(2X, 3Y) This is an example of perfect complements The MRS is undefined at the vertex where 2X=3Y But lets graph the indifference curve, remember they L shaped
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`2xy (dy)/(dx) = x^(2) 3y^(2)`Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyLet's factorise the right side of the equation Next, we want to separate the variables, ie we want all the 'y' terms on the left side and all the 'x' terms of the right side
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The factors are (xy)(xy) or (xy)^2 We need to factor the trinomial x^22xyy^2 The factors of x^2 = (x)(x) The factors of y^2 = (y)(y) Since the second sign is positive we are adding the factors meaning the signs of the factors need to be the same Since the first sign is negative both signs must be negative The factors are (xy)(xy) or (xy)^2 Check by FOIL FirstsSolution for Solve dy/dx=2xy/(x^2y^2) Q A group of 150 tourists planned to visit East AfricaAmong them, 3 fall ill and did not come, of th A Consider the provided question, First draw the Venn diagram according to the given question, Let K rY = 1/(4 x^2)
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyHow can I solve the differential equation x^2 dy/dx=yxy, y(1)=1?I think it's reasonable to do one more separable differential equation from so let's do it derivative of Y with respect to X is equal to Y cosine of X divided by 1 plus 2y squared and they give us an initial condition that Y of 0 is equal to 1 or when X is equal to 0 Y is equal to 1 and I know we did a couple already but another way to think about separable differential equations is really all
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Libros de Texto En PDFÁlgebra de Baldor http//beteshiscom/pQtEcuaciones Diferenciales con Aplicaciones de Modelado http//beteshiscom/pSNFísica universConsider x^ {2}y^ {2}xy22xy as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest power x^ {2} and m divides the constant factor y^ {2}y2 One such factor is xy1 Factor the polynomial by dividing it by this factorSOLUTION 1 Begin with x 3 y 3 = 4 Differentiate both sides of the equation, getting D ( x 3 y 3) = D ( 4 ) , D ( x 3) D ( y 3) = D ( 4 ) , (Remember to use the chain rule on D ( y 3) ) 3x 2 3y 2 y' = 0 , so that (Now solve for y' ) 3y 2 y' = 3x 2, and Click HERE to return to the list of problems SOLUTION 2 Begin with (xy) 2 = x y 1 Differentiate both sides
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All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}yxy^ {2}=13 x 2 y x y 2 = 1 3 Subtract 13 from both sides of the equationY=1/ (4x^2) Cheggcom math advanced math advanced math questions and answers Y'=2xy^2;Solve ( d^2 y(x))/( dx^2) 3 ( dy(x))/( dx) 2 y(x) = e^x/(e^x 1) The general solution will be the sum of the complementary solution and particular solution Find the complementary solution by solving ( d^2 y(x))/( dx^2) 3 ( dy(x))/( dx)
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The equation x^2 y2xy^3=8defines y as a function of x,y=f(x), near x=2, y=1 a) Find dy/dx b) Now, find the slope of the curve x^2y2xy^3=8 when x=2, y=1 Calculus I am having trouble differentiating x^2 2lny = y (solving for dy/dx) I know that I need to do implicit differentiation, but the answer I get is not correct y^2 = x^2(2lnx c) We can rewrite this Ordinary Differential Equation in differential form (x^2 y^2) \ dx xy \ dy = 0 A as follows \ \ \ \ dy/dx = (x^2 y^2)/(xy) dy/dx = x/y y/x B Leading to a suggestion of a substitution of the form u = y/x iff y = ux And differentiating wrt x whilst applying the product rule dy/dx = u x(du)/dx Substituting into the DE BEquations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations (4x^2y)(2xy^2) so that you understand better
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Note that mathy'=\dfrac{x^2y^21}{x(2yx)}/math The substitution mathu=(2yx)^2/math transforms this to a linear DE math\begin{align*}u' &= 2(2yx)(2y'1Popular Problems Calculus Find dy/dx 2xyy^2=1 2xy − y2 = 1 2 x y y 2 = 1 Differentiate both sides of the equation d dx (2xy−y2) = d dx (1) d d x ( 2 x y y 2) = d d x ( 1) Differentiate the left side of the equation Tap for more steps By the Sum Rule, the derivative of 2 x y − y 2 2 x y y 2 with respect to x x is d d x 2Y= ( 1 zc Cuando x = 0, y = 0, así que necesariamente c = 0;
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